The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(n^1, INF).

(0) Obligation:

Runtime Complexity TRS:
The TRS R consists of the following rules:

addlist(Cons(x, xs'), Cons(S(0), xs)) → Cons(S(x), addlist(xs', xs))
addlist(Cons(S(0), xs'), Cons(x, xs)) → Cons(S(x), addlist(xs', xs))
addlist(Nil, ys) → Nil
notEmpty(Cons(x, xs)) → True
notEmpty(Nil) → False
goal(xs, ys) → addlist(xs, ys)

Rewrite Strategy: INNERMOST

(1) CpxTrsToCpxRelTrsProof (BOTH BOUNDS(ID, ID) transformation)

Transformed TRS to relative TRS where S is empty.

(2) Obligation:

Runtime Complexity Relative TRS:
The TRS R consists of the following rules:

addlist(Cons(x, xs'), Cons(S(0), xs)) → Cons(S(x), addlist(xs', xs))
addlist(Cons(S(0), xs'), Cons(x, xs)) → Cons(S(x), addlist(xs', xs))
addlist(Nil, ys) → Nil
notEmpty(Cons(x, xs)) → True
notEmpty(Nil) → False
goal(xs, ys) → addlist(xs, ys)

S is empty.
Rewrite Strategy: INNERMOST

(3) DecreasingLoopProof (EQUIVALENT transformation)

The following loop(s) give(s) rise to the lower bound Ω(n¹):
The rewrite sequence
addlist(Cons(x, xs'), Cons(S(0), xs)) →⁺ Cons(S(x), addlist(xs', xs))
gives rise to a decreasing loop by considering the right hand sides subterm at position [1].
The pumping substitution is [xs' / Cons(x, xs'), xs / Cons(S(0), xs)].
The result substitution is [ ].

(4) BOUNDS(n^1, INF)